2023漳州高三三检语文答案

2023漳州高三三检语文答案试卷答案,我们目前收集并整理关于2023漳州高三三检语文答案得系列试题及其答案，更多试题答案请关注微信公众号：趣找答案/直接访问www.qzda.com(趣找答案)

2023漳州高三三检语文答案试卷答案，以下是该试卷的部分内容或者是答案亦或者啥也没有

8.B设g(x)=e[f(x)-1],则g'(x)=ef(x)+ef(x)-e.因为f(x)+f(x)>1,所以ef(x)+ef'(x)>e,即ef(x)+ef(x)-e>0,故g(x)在R上单调递增.因为f(x)是定义在R上的奇函数,所以f(0)0,所以g(0)=-1,不等式ef(x)>e-1,即g(x)>g(0),则x>0.

Writing6MyFavoriteSportHello,everyone.Myfavoritesportisswimmingandmyrcasonsareasfollows.First.it'sanaffordablesportandwontcostmemuch.Itwon'tneedmuchmoneyformetohaveaswimintheriverorapool.AndidontneedacoachunlessIwanttobeaprofessionalcompetitor.Second,swimmingisbeneficialtoourheartsandlungs.Inadditiontoitsphysicalbenefits,swimmingisalsoaneffectivewaytorelax.Spendinghoursinthepoolinhotsummerisalwaysmyfavoritepastime.Inconclusion,asaverygoodworkout,swimmingcangiveyoupeaceofmindtocontinuewithyourday.

20.参考答案解:(1)设Q(x,y),D(x0,y),因为2EQ=3ED|,Q在直线m上,所以x=x,lyo|=因为点D在圆x2+y2=16上运动,所以x3+y2=16,②将①式代人②式即得曲线C的方程x2+3y2=16,即计+=1.(5分)(2)直线PA,PM,PB的斜率成等差数列证明如下:由(1)知椭圆C:3x2+4y2=48,直线l的方程为y=k(x-2代入椭圆方程并整理,得(3+4k2)x2-16k2x+16k2-48=0.(8分)设A(x1,y1),B(x2,y2),直线PA,PMPB的斜率分别为k1,k2,k则有x1+可知M的坐标为(8,6k)所以k+k=2-3+y=3k(x2k-1,2k=21.(10分)所以k+k3=2k2所以直线PA,PM,PB的斜率依次构成等差数列.(12分),

2R,临界情况如图所示.设最大半径为ro,所对应的最小磁感应强度为B2,运动轨迹分别与磁场右边界与MN板相切,根据几何关系可得r=(d-r)2+(ra-R)2(1分)可得r。=d+R-√2aR<2R(1分)m√2mrUceB.(1分)B故当2R

21.①诗都有标题②无题也是我们诗歌的传统③为文造情也(每处2分意思对即可)22.参考示例:①我国最早的诗歌总集《诗经》所收集的诗歌,原来均无标题,现在人们看到的标题都是被后人加上去的,(3分,其他修改方法正确亦可给分)

2023漳州高三三检语文答案