2023莆田二检历史答案

2023莆田二检历史答案试卷答案,我们目前收集并整理关于2023莆田二检历史答案得系列试题及其答案，更多试题答案请关注微信公众号：趣找答案/直接访问www.qzda.com(趣找答案)

2023莆田二检历史答案试卷答案，以下是该试卷的部分内容或者是答案亦或者啥也没有

15.【关键能力】本题通过波的传播问題考查考生的理解能力和逻辑推理能力【解题思路】(1)t1=0.1s时波恰好传播到B点,因此波速10.ms=80m/s(1分)在!1=0.1s时质点A位于波峰,质点B恰好开始振动,波源此时刚好经过平衡位置向y轴负方向振动,因此有0A=(n+)A(n=0,1,2,…)(1分又由于2A>O4>A,所以n=1,则波长A=1.6m(1分)波源振动周期r=A=0.02(1分)(2)在t1=0.1s时间内,质点C振动了0.05s=25T,质点C从平衡位置开始振动,经2.5T恰好又经过平衡位置,因此振动位移为0(1分)通过的路程为s=2.5×4D=1m(2分)

22.解:(1)在直线l的参数方程中消去参数t,可得直线l的普通方程为x-√6y-8=02分曲线C的极坐标方程可化为2+psm2=8,将x=pos0,y=psin代入方程,可得x+2=8如这74分故直线的普通方程为x=⑤y-8=0:曲线C的直角坐标方程为+=1(2)设点Q的坐标为(22cosa,2sina)(a∈[O,2x)由点P为直线l上任意一点,则PQ的最小值即为点Q到直线l的距离的最小值7分Q到直线的距离为12n26-8-4a(a+3)=88-4287-4√145丌√787-4√14故PQ|的最小值为10分

,1.【答案】B【解析】糖类中的纤维素、核糖等不能作为能源物质，A项错误；位于细胞膜上的糖类和蛋白质可构成糖蛋白，与正常细胞相比，癌细胞膜上的糖蛋白较少，B项正确；蔗糖为二糖，不能被人体细胞直接吸收，C项错误；细胞内糖类的水解或合成需要酶参与，这些酶的化学本质是蛋白质，D项错误。,,3.【答案】D【解析】内质网内连核膜，外连细胞膜，在结构上直接相连，A项正确；病理状态下内质网的肿胀是膜胀大，体现了细胞膜的流动性，B项正确；内质网参与胰岛素的加工过程，发生内质网应激时内质网的功能失衡，有可能导致胰岛素合成不足而患糖尿病，C项正确；高尔基体与植物细胞壁的形成有关，而不是内质网，D项错误。,

第三节书面表达wersionDear Sir or MadamMy name is Li Hua. As an exchange student fromChina, I am studying in a local school. I am reallydelighted to learn that a volunteer for your Chinese culturallic exhibition is required and I'm confident that I amtruly fit for thestart with, my advantage first lies in the fact that IChina and used to beand quite familiar with Chinese relics. Further-more, being an outgoing and optimistic boy, I am good atcommunicating with others and introducing Chinese cultureto the world is always my honor and my pleasure. Finallythere is no problem with my spoken English, as I havelived here for almost a year and I have no difficulty commu-dicating with others in EnglishI would really appreciate it if you can offer me thechance to be a volunteer in your museum. I am looking forward to your early reply.Li Hua

17解:(1)设抛物线的方程为y2=2px(p>0),圆(x-2)2+y2=4的圆心坐标为(2,0),即抛物线的焦点为F(2,0),(3分)∴p=4,…∴抛物线的方程为y2=8x5分(2)由题意知直线AB的方程y=2(x-2),(6分)即y=2x-4,代人y2=8x,得x2-6x+4=0,△>0,设A(x1,y),B(x2,y2),则x1+x2=6,则|AB|=x1+x2+p=6+4=10(10分)