2023河北省邯郸高三一模语文答案汇总

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6.A【解析】氧气在正极上得电子电极Ⅱ为正极酸性环境屮电极反应式为O2+4H+4e=2H2O.故A错误;电池的总反应为2O+O)2==2CO,工作…段时间后溶液的H几乎不变,故B正确;该电池通过光照发生化学反应,形成原电池,将光能转化为化学能和电能,故C正确;根据图示,光照后,电极b上,Fe失去电子,电极反应式为Fe2+e=Fe+,故D正确。故选A。

7.B【解析】由题给信息可知铂纳米电极a为正极,氧气在电极a上得电子,故A正确;质子交换膜只允许氢离子通过,不允许Na通过,放电时,原电池内部的阳离子向正极移动.氢离子通过质子交换膜向电极a移动.故B错误;含有乳酸氧化酶的碳纳米管电极b为负极,负极反应式为C2HO3+3H2(-12e==3CO2↑+12H故C正确;根据电流强度,判断乳酸含量,利用该技术可监测人体乳酸含量,进行疾病诊断故D正确。故选B

1.【答案】B【解析]:-11下…计评=×1+1+1+i(1+)2+0)(1-=21,∴:1=2,故选B

34.[物理——选修3-4(1)BCD(5分)解析:(1)本题考查机械波。由同侧原理可知,=0时刻,x=1m处的质点与x=5m处的质点均沿y轴正方向运动,A项错误;两列波相向运动,1=22XS=1.55相週B项正确;两列波的波长均为2m,x3m处的质点到两波源距离差△x=1m=入,两列波的起振方向相反此点为振动加强点,故C项正确=2s时,甲波传播到x=35m处时正处于波谷、乙波传播到x=35m处时正处于波峰所以质点的位移r=3cm-5cm1=-2cm,故D项正确;任何障碍物都可以使光发生行射现象,若要发生明显的衍射现象,则障碍物尺寸需要小于或和波长尺寸相当,故E项错误(2)解:①设光从O点射入,反射光交于A点,由题意画出光路图如图所示设折射角为r,平行玻璃砖的折射率为n由折射定律有2=n(2分)根据几何关系有l=2tanr(2分)+4dsin所以解得n=(1分)②光在玻璃砖中传的速度v=(1分)折射光在玻璃砖中传播的距离s++(2)2(1分)所以该光从人射到从下表面折射出来的过程中在玻璃砖中传播的时间t=(1分)解得t=(4d+p)sin。(2分)

第二节One possible versionDiamond hurriedly ran to the bird. Approaching thebird. he ran around themelt the bird. and thenbarked at his master. Gunnar understood the boy was asking him to help the bird. So, he picked it up gently. Aftercareful examination, Gunnar told his boy that Bibi didn'tlf indoors Considering that the bird wasn't wellgH to leave, he put him back in the basket, with andded bite of sweet potato as well. He decided to set himfree the next day, when he would be fully recoveredAfter Bibi s recovery, Gunnar placed him back out onthe balcony. Suddenly, the bird started to sing, as if hewere expressing thanks to Diamond. Then he spread hiswings,flying away. A while after the bird had gone, Isaid to Diamond: Where is Bibi?'"recalled GunnarHe looked at me, very sharply, then jumped on the sofaand ran directly to the balcony door. He knew exactly whatI was talking about.

9D【解析】“诗人孤独、寂寞之情”有误,应该是“增添了一份生机、乐趣”。10.①全诗通过诗人江边漫步、野鸭浮游、藕叶翻滚、燕子翻飞、桐花拂动、渔船靠岸、缫车鸣响、蛙声阵阵等,描绘出一幅乡间清幽闲适、充满生机的画面。(3分)②诗人通过再现农村的生活情景和村民的精神状态,表现出村民生活的愜意和无拘无束,表达了诗人内心的宁静和隐居的惬意。(3分