2023江苏省常州高级中学高三上学期1月月考生物答案

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2023江苏省常州高级中学高三上学期1月月考生物答案试卷答案，以下是该试卷的部分内容或者是答案亦或者啥也没有

18.(10分(1)+3(1分)(2)①酸式(1分)溶液由无色变为淡紫色,且半分钟不褪色(2分)②2ab(2分)③367%(2分)3)CaCoA(sCa'(a)+CaOa(aq),多喝水沉淀溶解平衡正向移动,有利于结石的消融(2分)

(1)A.实验中用砂和砂桶的总重力表示小车所受合力,为了使小车的合力近似等于砂和砂桶的总重力,砂和砂桶的总质量应远小于小车的质量,故A正确B.实验所用电磁打点计时器的工作电源应选用电压约为6V的交流电源,而蓄电池提供的是直流电源,故B错误C.实验时,应先让打点计时器正常工作,后释放小车,才能够在纸带上打出足够多的点,故C正确;D.平衡摩擦力时,不应挂上空砂桶,故D错误。故选:AC。(2)C点的读数为1.65cm,E点的读数为355cm,CE的距离rCE=(355-1.65)cm=1.90cm。中间时刻的速度等于该时间段的平均速度,所以打点计时器在打D点时纸带的速度WCE1.90UD2T2×0.02×10-2m/8=0.475m(3)根据动能定理:W=△E,小车动能变化△E与绳子拉力对小车所做功W的关系图象是经过原点的一条直线,故A正确。故答案为:(1)AC;(2)0.475(0.450~0.500都对);(3)A

ngHmgR(1)H2+R2H2+R2(2)./29HR【解析】(1)当筒不转动时,物块静止在A点,受到重力、摩擦力和支持力三力作用而平衡,由平衡条件得摩擦力的大小=nosing-m9HH2+R2支持力的大小FN=m9cos0=mgRH2+R2(2)当物块在A点随筒做匀速转动且其所受到的摩擦力为零时,物块受到重力和支持力作用,它们的合力提供向心力,设筒转动的角速度为心,则Rmatane=mw2由几何关系得tan∥≈∥R联立解得u=y<9∥R

第三节书面表达wersionDear Sir or MadamMy name is Li Hua. As an exchange student fromChina, I am studying in a local school. I am reallydelighted to learn that a volunteer for your Chinese culturallic exhibition is required and I'm confident that I amtruly fit for thestart with, my advantage first lies in the fact that IChina and used to beand quite familiar with Chinese relics. Further-more, being an outgoing and optimistic boy, I am good atcommunicating with others and introducing Chinese cultureto the world is always my honor and my pleasure. Finallythere is no problem with my spoken English, as I havelived here for almost a year and I have no difficulty commu-dicating with others in EnglishI would really appreciate it if you can offer me thechance to be a volunteer in your museum. I am looking forward to your early reply.Li Hua

27.(1)254(2分)(2)Li2SO1(2分);,N2(1分);“N2H(1分)(3)①b;9.5×10-2(各2分)②加压;1.4(各2分)