2023揭阳二模地理试题答案

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2023揭阳二模地理试题答案试卷答案，以下是该试卷的部分内容或者是答案亦或者啥也没有

,16.【解析】(1)由messin=mv2(2分)得v=√2gsin0=1m/s(2分)(2)金属棒从释放到运动至M1P1的时间t=gsIn=0.2s(1分)在t=0.1s时,金属棒还没进入磁场有E1=△BLd=0.6v(2分)此时,R2与金属棒并联后再与R1串联,R中=3Q,是(2分)由图乙可知t=0.2s后磁场保持不变,金属棒在磁场中运动的时间t=d=0.2s(1分)故在t2=0.25s时金属棒还在磁场中运动,电动势Ey=BLu=0.6V(1分)此时R1与R2并联,R总=3,得R1两端的电压U1=0.2V1分)电功率P=R,故在t=0.1s和t2=0.25时刻电阻R1的电功率的比值P2U,7=4(2分),,12.(1)红(2分)(2)64mA(2分)(3)49(2分)(4)NV(或0-7V)(3分),

23.B【解析】由图可知,在pH=0~6范围内,不存在H2A分子,说明H2A的第一步电离是完全的,H2A的电离方程式为H2A=H++HA-,HAH++A2-,A项错误;由pH=3时的数据可知,HA-的电离常数K。=1×10-3,温度不变,电离常数不变,故pH=5时,电离常数K。1X1Q-×(A=1×10c(HA)=100,B项C(HA)正确;因K.=1×10-3,故NaHA溶液中仍以Na+HA-为主,故离子浓度:c(Na+)>c(HA-)>c(H↑)>c(A2-)>c(OH-),C项错误;根据H2A的电离方程式可知,Na2A溶液中c(H2A)=0,D项错误。

16.A【解析】由图可知,过程I中1个水分子中的化学键断裂,过程Ⅱ另一个水分子中的化学键断裂,过程Ⅲ中形成了新的水分子,故起始时的2个H2O最终都参与了反应,A项正确;过程I、Ⅱ中水分子中的化学键断裂,为吸热过程,B项错误;过程Ⅲ中形成CO2、H2O和H2,H2中的化学键为非极性键,C项错误;催化剂不改变反应的△H,D项错误

3.A由已知得2>0>2,+n(4-x)的定义域为(2,4).故选A4-x>0,解得所以函数f(x)(题封的平面和:道)

doing sth.“期待做某事”,故have改为havi第二节书面表达【参考范文】The sumer vacation i am looking forward to is coming sooie: In order to have a full and meaningful summer vacation. I made asummer vacation plan.I plan to go to bed early and get up carly every day.and keepTt: doing exercise. Easickex.I want to learn swimming which is very gordfor my health. in order to keep heaithy and energetic.I need to eat at: balanced diet On the one hand. I am going to finish my summerhomework on time. O)n the other hand. I am going to rcad morebooks, including an English novel. By reading more books.I canE: broaden my horizon. As the saying gocs, it is hetter to travel tenthousand miles than to read ten thousand books, so I plan to travelf: to Hangzhou with my parentsI hope I can have a colorful summer vacation.