2023江苏省南通市高二下学期期末质量监测英语试题答案
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2023江苏省南通市高二下学期期末质量监测英语试题答案-福建高考早知道试卷答案,以下是该试卷的部分内容或者是答案亦或者啥也没有
4.B解析:本题考査阿伏加德罗常数的运用。水中也有羟基,A项错误;铁亐稀硝酸完全反应时,铁可能被氧化成亚铁离子,也可能被氧化成铁离子,或者二者都有,所以5.6g铁与稀硝酸完全反应时转移的电子数目应在0.2NA~0.3NA之间,B项正确;KHCO3固体中不含CO,C项错误;该反应净产生的中子(bn)数为0,D项错误。
17.(12分)(1)N(2分)团计计计[2分)3d(2)BD(2分)(3)Cu+核外电子处于较稳定的全充满状态(2分)(4)铜失去的是4s电子,锌失去的是全充满的4s2电子,需要的能量更多(2分)(5)共价(2分)【解析】(1)基态Cu原子的核外电子排布式为ArJ3d04s,核外电子占据的最高能层符号是N,价电子排布图为卧什计计计团团。3d4s(2)当铜或铜盐在火焰上灼烧时,原子中的电子吸收能量,从能量较低的轨道跃迁到能量较高的轨道,但处于能量较高轨道上的电子是不稳定的,很快跃迁回能量较低的轨道,同时将多余的能量以光的形式放出,形成焰色反应。故选B、D项。(3)基态Cu的价电子排布式为3d,处于较稳定的全充满状态,基态Cu2的价电子排布武为3d9,故高温条件下Cu2O比CuO更稳定。(4)铜失去的是4s电子,锌失去的是全充满的4s2电子需要的能量更多,故铜比锌的第一电离能小。(5CuI中Cu元素与I元素的电负性相差不大,CuI属于共价化合物
23.解:(1)据题意,得x-2|+|x+2|≥-3x+4讨论当x<-2时,-(x-2)+[-(x+2)]≥-3x+4,得x≥4,此时无解;1分当-2≤x≤2时,-(x-2)+(x+2)≥-3x+4,得x≥0,所以0≤x≤2;2分当x>2时,(x-2)+(x+2)≥-3x+4,得x≥4,所以x>23分综上,所求不等式的解集为{x|x≥04分证明:(2)因为f(x)=x-21|+|x+2(x∈R),所以f(x)m=4,即a=4又因为m+n=a(m>0,n>0)所以m+n=4(m>0,n>0)6分n=4(m+0(+1)4(2+m+m8分即m+n≥1,当且仅当m=n,m=n=2时,等号成立9分即m+n≥m.,
Paragraph 1A seat beside her was empty, and Dannis occupiedHe ielt a wave of anger swept over him. "Where is mywallet?"he yelled. The black-haired girl glanced up fromher reading, with a confused look on her face. Dannis stoodup, glared at her and shouted, "You stole my wallet! "Thecrowds began to gossip. The girl turned deadly palelooking so restless that words failed her. A strange silencehung in the air. Abruptly, she leaped from the seat.Paragraph 2:The girl ran and Dannis ran after her. After awhile, Dannis finally grabbed her by the arm. At exactlyhat moment, a policeman approached them and askedbout what happened. Dannis hastened to explain it whilethe girl frowned with a shake of her head. After furtherenquiries, the policeman took out a wallet and banded it toDannis,adding that someone had found it in the toiletWhat a mistake he had made! Overwhelmed byyDannis made an apology to thegirl.
16-20 AEBDG
2023江苏省南通市高二下学期期末质量监测英语试题答案-福建高考早知道版权声明
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