2024四川省绵阳南山中学高三上学期零诊考试文科数学试题及答案

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第二节【参考范文】On that Sunday, I paid a visit to Willard's family. On entering his house, I was surprised to find a barelyempty room with a broken bed and a dirty sofa. It seemed as if the house had been unoccupied for a longtime. willard told me his mother died and that his father was missing when he was five, leaving him to livewith a sick grandma. When asked why he had given the two quarters, Willard mumbled, "I just want to helpothers by contributing my milk money. I couldn t help bursting into tears. thinking I should help him breakhis silence. On my way home, I made up my mind to do something for the kind-hearted boy so that he couldreally be a member of our class.The next day, I had a special class for willard. I shared his story with the whole class and said, Now,on behalf of the people in need, I should say thanks to willard, you are great! After a silence, all thestudents clapped, saying"Willard, you are great! and they walked to him and hugged him tightly. willardfelt uncomfortable at first when hugging them. He gave a bashful smile as his classmates complimented hiscontribution. Finally, he opened his arms wide to embrace his friends. A friend relationship was built andWillard's silence was broken by a smile on his face.

11.参考答案ACD说明分析E设金属的逸出功为W,光电效应方程为Ek=hy-W0。A选。由上式知光电子的最大初动能E与光的强度无关B不选。由上式知Ekν图像的斜率表示普朗克常量h,则两条图线与ν轴的夹角相等C选。图像纵轴截距的绝对值为逸出功,则乙的逸出功大,某一频率的光能使甲发生光电效应但不一定能使乙发生D选。实验中的遏止电压U,则有E=eU。结合上式知,ν增大则Ek增大,则U增大

18.参考答案(1)物块圆周运动至A点时由牛顿第二定律得7mg-mg=m(2分)解得vA=√6R①(2分)O,2)物块圆周运动至B点时设管道对其向下的压力为FN,由牛顿第二定律得FN+mg=mR②(1分)A→B运动过程由机械能守恒有m=mg·2R+mt③(1分)解①②③式得FN=mg④(2分)由牛顿第三定律知,物块对管道的压力为mg,方向竖直向上。(1分)(3)设斜面末端为C,其速度为vcC→·A过程机械能守恒有mv+mgh=mh⑤(1分)应用几何关系得h=R(1-sin30°)⑥(1分)沿斜面向下加速运动过程,由牛顿第二定律得mgcos30-omgsin30=ma⑦(2分)由运动规律得vc=at⑧(1分)联立①⑤⑥⑦⑧式得t=2/5R(2分)g