2024届衡水金卷新高三联考生物试题答案

2024届衡水金卷新高三联考生物试题答案-福建高考早知道试卷答案,我们目前收集并整理关于2024届衡水金卷新高三联考生物试题答案-福建高考早知道得系列试题及其答案，更多试题答案请关注微信公众号：趣找答案/直接访问www.qzda.com(趣找答案)

2024届衡水金卷新高三联考生物试题答案-福建高考早知道试卷答案，以下是该试卷的部分内容或者是答案亦或者啥也没有

第一节短文改错（共10小题：每小题1分，满分10分）Nowadays,wecanseephubberswatchingtheirmobilephoneseverywhere.Theycan'stopsendingmessages,surfingtheInternet,listeningmusicandeventakingphotosbytousingthemobilephone.Actually,phubbingdisturbsnotonlyourstudyandour.Ontheonehand,phubbersbutaseplentyofmclphonegamesadsdingmeasparticuarynhecntheplayingcther,usingthemobilephoneforalongtimecanleadtohealthyproblems.healthAsfarasIamconcemned,itishightimethatweputdownthemobilephoneandraiseourraisedheadsup.Docherishthatisaroundusandappreciatethesceneriesaheadofus.Onlywhenweh过sceneryusethemobilephonereaonbecanyourealizethehappinessoflife.reasonablywe

36-40CGAEB

14.一2019【解析】lga1+lga2+…+ Ig asos=1009lg(ar asos)+lg aoto=20191g a1oto=-2019

(17)(本小题满分12分)解:(1)当n=1时,a1=3S-2=3a1-2,解得a1=1当n≥2时,an=3。-2,an1=3Sn1-2,两式相减得anan1=3a化简得an=an→,所以数列{a2}是首项为1,公比为一的等比数列所以(Ⅱ)由(可得m方法一:错位相减法(22(2)*((2)中(2(w(两式相减得2=1+(2所以数列的和({3()……12分方法二:裂项相消法因为=:(2-c-(33)((3)(所以=(-c2)+(2c)+…+(cn-cn)=×、12分