江浙皖县中发展共同体2024学年高三第一学期10月联考生物试题及答案

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第二节书面表达【写作思路】根据试题要求,考生需要写一篇记叙文,记述身边一位值得尊敬和爱戴的人。首先考生需要介绍自己最尊敬和爱戴的人是谁,简单地介绍一下他(她)。然后,陈述为什么他(她)值得尊敬和爱戴。最后,可以对前文进行一个总结,使文章结构严谨。本文的写作重点在"尊敬和爱戴的原因",考生可围绕这个要点适当拓展,从性格特点、处事风格等方面展开写作。【范文赏读】The most beloved and respected person around me is my teacher, Ms LiThough she has been teaching English for twenty years, she is still passionateabout teaching. She is kind and considerate towards us just like our dear motherWe all respect her because she always tries new ways to make her classes livelyand interesting. Hardworking and knowledgeable, she is one of the best teachersin our school. When we have a problem, we will turn to her for help. She alwaystalks to us patiently and helps us to find a solution. In our eyes, she is not onlyour teacher, but also our best friend. Those are why she deserves our respect【亮点词句】亮点词汇: beloved, respected, be passionate about, be consideratetowards, turn to sb. for help, in one's eyes亮点句式:Why引导的表语从句( why she deserves our respect)

7.D【解析】本题考查带电粒子在电磁复合场中的运动。根据左手定则,正离子受到竖直向下的洛伦兹力,负离子受到竖直向上的洛伦兹力,则正电荷聚集在N一侧,负电荷聚集在M一侧,则M点的电势低于N点的电势,A、B、C错误;正负离子达到稳定状态时,有qnB∠q,可得流话B,流量Q=S=md,Um,D正确U4Bd4B

4.c【解析】本题考查理想气体状态方稈、热力学第一定律。C→A过程气体体积减小,外界对气体做正功,气体发生等温变化,即ΔU=0,内能不变,故A错误;A→B过程气体体积增加,气体对外做功,做功的大小等于A→B的图线与体积轴所围成的面积,B→C过程是等容变化,气体不做功,C→A过程是等温过程,外界对气体做功,其做功的大小等于C-图线与体积轴所围成的面积,A→B和C→A图线与体积轴所围的面积不相等,气体对外做的功大于外界对气体做功,故整个循环过程中气体对外做功,故B错误:A→B过程是绝热过程,气体对外做功,则W<0,Q=0,根据热力学第定律△U=W+Q,可得△U<0,则内能减小,故C正确;B→C过程是等容过程,外界对气体不做功,气体压强降低,由C得气体温度降低,则气体的内能减小,故D错误。