2023四川省成都七中高2023届三诊模拟测试语文试题答案
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2023四川省成都七中高2023届三诊模拟测试语文试题答案试卷答案，以下是该试卷的部分内容或者是答案亦或者啥也没有
8.A【解析】]∵2cos2a=1+sin2a,;2(c3丌cosa-sina)(cosa+sina)=(cosasina可得cosa+sIna>0,∴2(cosa-sina)=cosa+sina,可得cosa3sina,即tanasin2acosa2sinacosacos"atana+15故选A1+sinatcosatana+14
14.(理科)12【解析】:(2-mx3)(x-3)的展开式中x3系数为-n-所以m其中x3的系数为2C5+(-m)·C3(-3)3=12,故答案为12(文科)-1【解析】当c=0时,直线为2x+1=0,不是抛物线切线,故2不妨设切点为(x0,x02),则y=2xo=-,且2x0-cx2+1=0,+1=0,解得c=-1,故答案为
书面表达One possible version:NOTICEA sports meeting will be held in the playground of our school from next Thursday to FridayAs you know, the pressure of study is very heavy now, especially for those senior 3. So the purpose of the sports meeting is to letevery student get relaxed, as a result of which we students can live happily and heal thilyEveryone is welcome to take part in it. Those who perform excellently at the sports meeting will get prizes. But don' t take theresults so serously because taking part is more important than the result. Good luck to everyone!
"2.C【解析】由已知得集合A={x|x>1},集合B={x|-12023四川省成都七中高2023届三诊模拟测试语文试题答案
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