2023四川省南充市高2023届高考适应性考试理科综合试题答案
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2023四川省南充市高2023届高考适应性考试理科综合试题答案试卷答案,以下是该试卷的部分内容或者是答案亦或者啥也没有
【语篇导读】本文一篇说明文。文章主要介绍了机器人包裹递送服务。12.D词义猜测题。根据画线词后的内容可知,此处指为了接收快递而重新安排生活的麻烦将成为过去,由此可知画线词词义为“麻烦”,故D项正确13.A细节理解题。根据第三段中“Thepackagedeliveryserviceisnotavailabletoeveryonejustyet."可知,快递机器人递送包裹的服务还没有提供给每一个人,也就是说它的服务范围有限,故A项正确。4.C细节理解题。根据第四段中的“Bygivingcustomerscontrolofwhendeliveriesoccur,StarshiTechnologiesisofferingitsserviceasawaytobattlepackagethef.”可知,该公司将让客户控制送货时间的服务作为打击包裹盗窃的一种方式,故C项正确5.B推理判断题。根据文章最后一句“OnceapackageisdeliveredtotheStarshipaddress,customersreceiveatextthatallowsthemtoscheduleahomedeliveryviarobot.”可知,一且包裹被送到StarshipDeliveryAddress,客户就会收到一个信息,让他们通过机器人安排家庭递送,由此可知,它能够为顾客安排递送机器人,故B项正确。
16.答案:(1)散入珠帘湿罗幕狐裘不暖锦衾薄(2)饨郁邑余佬傺兮吾独穷困乎此时也(3)取之无禁用之不竭
63分)A7(3分)D8(4分)①老题材可以有新写法:②作家自身内涵比技巧更重要。(每点2分,其他答案言之成理可酌情给分96分)①兼具阻滞、关闭和畅通、开放的特点;②连接历史和未来:③具有文化色彩。(每点2分,其他答案言之成理可酌情给分
4.B【解析】本题考查宋代手工业。从材料信息看,管手工业中出现了雇佣关系,人身依附关系松弛,劳动力具有自由之身,属于自由劳动力阶层敌逃B项。资本主义生产关系不仅仅是出现雇佣关系还包指集中的手工工场,为利润而生明中后期才出现资本主义萌芽排除A项;这一做法没有顺行会的束缚排除C项租系体现的是地主和农民的关系排除D项。
第三节One possible versionParagraph 1And not tery long after that, he made a surprisingdecision. He decided to use all his rights, preparing for hislife at the remote island. In the first year he sent troopsveterinarians and animal trainers to kill the wild animals ortrain them for good use. The task was so huge but it wasworthwhile. Then the king sent a lot of farmers to start awide rice field and began to grow rice. Next he had manyfacilities, from hospital to school, built. After that he senta lot of educated people there. At last he sent all his fami-lies to the islandParagraph 2Finally the time came when the king had to be thrownatay to the island. With many strong soldiers catchinghimsmiled. He had prepared everything for thefinalWhen he was sent lo the island, the island had takenon a new look. Everybody there lived a comfortable life andthe king was welcomed warmly by his people. THcheered, "Long live the wise king. "The wise king livedhappily ever after. The clever people live now in the worldto prepare for their life in the future
P>Si3)吡啶类化合物A中N原子形成双键,因此杂化类型是sP2,A中含有羟基,可与水分子形成分子间氢键,增强其水溶性,所以化合物A易溶于水。含Zn有机物B的分子结构中存在单键双键及N→Zn、O→Zn配位键(4)①AN晶体结构单元中含有M原子的个数为4+6X_6,N原子的个数为3+2×2+12×6=6即均是6个②根据“均摊法”,在氮化铁晶胞中,含有N原子数为1,Fe原子数为8×g+2=4,所以氮化铁的化学式为Fe4N,晶胞的体积为(a×10-10)3cm3,则该氮6化铁的晶体密度可表示为N4×10g/m3;由于能量越低越稳定,因此Cu替代晶胞中的Fe形成化学式为FeCu3N的氮化物(此时可推出Cu在面心位置,形成b位置Fe型)不稳定,则a位置表示晶胞中的顶点。2023四川省南充市高2023届高考适应性考试理科综合试题答案版权声明
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