2024届河北省石家庄市普通高中毕业年级教学质量检测（3月）地理试卷及答案

2024届河北省石家庄市普通高中毕业年级教学质量检测（3月）地理试卷及答案,答案汇总网收集关于2024届河北省石家庄市普通高中毕业年级教学质量检测（3月）地理试卷及答案的相关科目试卷及其答案，更多其他试卷答案请关注本网站！

【语篇导读】本文是夹叙夹议文,告诉我们“远亲不如近邻”的道理。8.A【解析】细节理解题。根据第一段 Muckprobably it is a close female friend calling to tell you thatshe has split up with her boyfriend again or perhaps simply that a good movie has just started on TV.可知最有可能来自一个朋友,故选A。9.C【解析】细节理解题。根据第三段 TV shows liktell us that our romantic relationships may not lastwe need to keep in touch with our close friends ifwant to survive.可知 rV shows like friends告诉我们亲密的朋友帮助我们面对生活中的困难。故选C。10.D【解析】推理判断题。根据最后一段 This is trueof Erika and Janes friendship. With Erika's family200 miles away, it is Jane who keeps a spare set of keysto Erikas apartment and waters her plants wheneverhe is away.可知Erka和Jane在日常生活中互相信任和支持。故选D1].A【解析】推理判断题。纵观全文,特别是最后have more to do with my life than ray paents and, therefore, I dont have to spend a lot of timeexplaining things to them. Friends are more up to datwith what is happening.可知远亲不如近邻。故选A

溶液中离26.(1)将原料粉碎(或适当提高酸的浓度或适当提高反应温度)(2分)(2)S1()2(2分)1.16×10°(2分)(3)加人碱中和硫酸,使平衡正向移动,提高钒的萃取率(2分)H2S01(2分)(4)6VO+C1O-+9H2O6V0+C1+18H(2分)(5)91%(2分)

长木板运25.解:(1)粒子在电场、磁场中的运动轨迹如图轨迹ACD所示(电场和磁场在图中未画出)粒子在电场中做类平抛运动,有=at(1分)其中d设粒子射出电场时与边界的夹角为1分)解得0=53(1分)解得即粒子射出电场时的速度大小为,方向与边界夹角为53.(1分)(2)粒子在磁场中运动时,由洛伦兹力提供向心力,有B(1分由几何关系可知rcos+r=d(1分)解得1分(3)若匀强电场的电场强度大小变为E设粒子射出电场时与边界的夹角为a,轨迹如图轨迹AC所示,则其中(1分解得a=37°(1分)解得(1分)解得=22(1分)粒子在磁场中运动时B(1分)解得=6(1分)设粒子射出磁场时速度与边界的夹角为,则有osa+rcos=d(1分)解得cosB(1分)即粒子射出磁场时,速度大小为言,与边界夹角的余弦值为(1分)

[db:内容1]